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trasher [3.6K]
3 years ago
5

Solve: -5 - (-1) I know it sounds really easy but i can figure this out

Mathematics
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

Step-by-step explanation:

-5+1

-4

Ipatiy [6.2K]3 years ago
5 0
The negatives would make -4 when put together
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H(a) = 2a+ 5g(a) = 3a−5Find h(a)+ g(a)
Alexandra [31]

Answer:

5a

Step-by-step explanation:

h(a) = 2a+ 5

g(a) = 3a−5

h(a)+g(a)

(2a+5)+(3a-5) (substitution)

2a+5+3a-5 (open parentheses)

5a+0 (solve)

5a

7 0
2 years ago
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What is the solution of log2x − 6 (256) = 4?
timama [110]
So D x= 5 is the right answer

6 0
3 years ago
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What is this? Please answer with an explanation
Pie

Answer:

5

Step-by-step explanation:

1. in order to calculate all the required values, it needed to solve:

\sqrt{x-5} \geq 0; \  \ x\geq 5.

2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.

3 0
2 years ago
Brittany buys 2.55 pounds of turkey for $5.96 per pound and 3.7 pounds of
Galina-37 [17]

Answer:

Brittany needs another $3.7405.              

Step-by-step explanation:

Per pound Cost of turkey = $5.96 per pound

The amount Brittany buys the turkey = 2.55 pounds

Brittany's cost for turkey = 2.55 × $5.96 = $15.198

Per pound cost for cheese = $3.35 per pound

The amount Brittany buys the cheese = 3.7 pounds

Brittany's cost for cheese = 2.55 × $3.35 = $8.5425

So,

Brittany's total cost = Turkey cost + Cheese cost

                                = $15.198 + $8.5425

                                = $23.7405

As brittany gave the clerk 20 dollars.

So, the amount she further needs will be:

$23.7405 - $20 =  $3.7405

Therefore, Brittany needs another $3.7405.                                                                      

8 0
2 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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