The surface area of the figure given is of: 61.3 yd².
<h3>What is the combined surface area of a figure?</h3>
The combined surface area of a figure is the area of each figure.
This figure is composed by:
- A triangle with base 6 yd and one leg 11.4 yd.
The area of the circle is given as follows:
![A = \pi r^2 = \pi \times 3^2 = 9\pi](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%5Ctimes%203%5E2%20%3D%209%5Cpi)
For the triangle, we need to find it's height, which is the <u>leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4</u>, hence:
h² + 3² = 11.4²
![h = \sqrt{11.4^2 - 3^2}](https://tex.z-dn.net/?f=h%20%3D%20%5Csqrt%7B11.4%5E2%20-%203%5E2%7D)
h = 11 yd.
Hence the area of the triangle is:
A = 0.5 x 6 x 11 = 33 yd²
The surface area of the figure is:
9pi + 33 yd² = 61.3 yd².
More can be learned about the surface area of at brainly.com/question/21208177
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The Answer is -16
I hope this helps
Answer:
Step-by-step explanation:
y= -5x/2+1
After factor simplification of the polynomial, The answer is D