B) sunlight travels through space - there is nothing to bounce off of until it hits an atmophere
2:16
2.5:20
3:24
4:32
5:40
1.5:12
Answer:
45.40
Step-by-step explanation:
First of all, the shape of rope is not a parabola but a catenary, and all catenaries are similar, defined by:
y=acoshxa
You just have to figure out where the origin is (see picture). The hight of the lowest point on the rope is 20 and the pole is 50 meters high. So the end point must be a+(50−20) above the x-axis. In other words (d/2,a+30) must be a point on the catenary:
a+30=acoshd2a(1)
The lenght of the catenary is given by the following formula (which can be proved easily):
s=asinhx2a−asinhx1a
where x1,x2 are x-cooridanates of ending points. In our case:
80=2asinhd2a
40=asinhd2a(2)
You have to solve the system of two equations, (1) and (2), with two unknowns (a,d). It's fairly straightforward.
Square (1) and (2) and subtract. You will get:
(a+30)2−402=a2
Calculate a from this equation, replace that value into (1) or (2) to evaluate d.
My calculation:
a=353≈11.67
d=703arccosh257≈45.40
Answer:
Step-by-step explanation:
First you need to convert it to a linear expression.
3x - y = 4
+3x +3x
-1y = 3x + 4
--- ----- -----
-1 -1 -1
y = -3x -4
6x - 2y = 7
-6x -6x
-2y = -6x + 7
---- ----- -----
-2 -2 -2
y = 3x - 3.5
-3x - 4 = 3x - 3.5
+3x +3x
-4 = 6x - 3.5
+3.5 +3.5
-0.5 = 6x
----- -----
6 6
-0.5
------ = x
6
