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Write equations for the horizontal and vertical lines passing through the point (4, -5).

raketka [301]

Answer:

Horizontal line: y=-5

Vertical line: x = 4

Step-by-step explanation:

As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).

To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.

Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5

To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.

Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4

Hence:

Horizontal line: y=-5

Vertical line: x = 4

8 0

3 years ago

Mr. Thomas deposited 2500 in a new bank account. The bank pays 6.5% interest compounded annually on this account. He makes no de

kotykmax [81]

Answer:

ghjghf

Step-by-step explanation:

8 0

3 years ago

Solve for a. -2(a-3)=12

meriva

Answer:

a=9

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas

Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is $= \frac{(n+1)}{2}$ .

$\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5$ position orders

$10^{th} \ and \ 11^{th}$ place an average of observations so, the

$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

4 0

3 years ago

Ecology: Wetlands Government agencies carefully monitor water quality and its effect on wetlands (Reference: Environmental Prote

Olegator [25]

Answer:

a) The variable of the study is: milligrams of nitrogen per liter of water.

This is the amount that needs to be measured and analyzed to reach conclusions in the study.

b) The variable is quantitative. The quantitative variables are those that represent quantities. This variables can be measured on a continuous or discrete scale. Then, all the variables that you can measure or count are quantitative variables(height of trees, number of passengers per car, wind speed, milligrams of nitrogen per liter, etc). On the other hand, qualitative variables are those that can’ t be measured, and they represent attributes, like apple colors (red, green), size of trousers (small, medium, large) and so on.

c) The population under study is the milligrams of nitrogen per liter of water that are in the entire lake. You can estimate the parameters of the population by taking samples (In the example, 28 samples are taken).

7 0

3 years ago