That's true. If the integers both have the same sign, then their product and quotient are both positive. If signs are different, then product and quotient are both negative.
Answer:
y=27 when x=2
Step-by-step explanation:
y varies inversely as the cube of x
y=k(1/X^3)
y=1 when x=6
y=k(1/X^3)
1=k(1/6^3)
1=k(1/216)
k=1÷1/216
K=1×216/1
k=216
find y when x=2
y=k(1/X^3)
y=216(1/2^3)
y=216(1/8)
y=216/8
y=27
Answer:
A)20 apples
B)Can only make 2 pies
C)Yes I think Is very close like probably just a lil bit more sugur but I think yes
D)Ohh so he doesnt have enough sugur I knew he needed a lil bit more sugur lol
Step-by-step explanation:
2x + -11 = k
Reorder the terms:
-11 + 2x = k
Solving
-11 + 2x = k
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 11 + 2x = 11 + k
Combine like terms: -11 + 11 = 0
0 + 2x = 11 + k
2x = 11 + k
Divide each side by '2'.
x = 5.5 + 0.5k
Simplifying