Given,
We can use L'Hopital's Rule to get,
![\lim_{x}^{a}\dfrac{2}{3-\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Clim_%7Bx%7D%5E%7Ba%7D%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Bx%7D%7D)
Now plug in a,
![\boxed{\dfrac{2}{3-\sqrt[3]{a}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Ba%7D%7D%7D)
Hope this helps.
r3t40
Answer:
-7x
Step-by-step explanation:
This is actually simpler than you might think. Just subtract.
4x-11x
-7x
30 percent is greater because o0.03 is actually 3 Percent
Answer:
option 1
Step-by-step explanation:
first we have to find the slopes of the lines
D(1, -2) E(3, 4)
y = m*x + b
m1: slope
m1 = (y2-y1) / (x2-x1)
m1 = (4 - (-2)) / (3 - 1)
m1 = 4+2 / 3-1
m1 = 6 / 2
m1 = 3
we do the same with the other 2 points
D(-1, 2) E(4, 0)
y = m*x + b
m2: slope
m2 = (y2-y1) / (x2-x1)
m2 = (0 - 2) / (4 - (-1))
m2 = -2 / 4 + 1
m2 = -2 / 5
m1 = 3 m2 = -2/5
for 2 lines to be perpendicular it must be met
m1 * m2 = -1
we check if they are perpendicular
3 * -2/5 = -1
-6/5 = -1 <-- no perpendicular
