Dominio:
(−∞,∞),{x|x∈R}
Rango:
(−∞,∞),{y|y∈R}
Answer:
Step-by-step explanation:
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
Divide by m to isolate .
To eliminate the square and isolate v, extract the square root.
let's rewrite it in a way that v is in the left side.
The < is just like and equal sign just looks a little different think of it that was for the first couple steps. So you have 13-3y<-5. First do, -5+13=8. Now you have -3y<8. Then your want to do 8 divided by -3 and you get=-2.666666667 and that equals y.
-2.7=y then make that equal sign into the normal sign again. -2.7
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:
This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."
In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of)
= 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7
Substituting these into the quadratic formula gives us:
As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
and
So the height is 8 feet at t = 3.63 and t=.12
It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.