so the triangle has the vertices of (2, 18) (-2, -4), and (6,12), that gives us the endpoints for each line of
(2, 18) , (-2, -4)
(-2, -4) , (6,12)
(6,12) , (2, 18)
![\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-(-4)}{6-(-2)}\implies \cfrac{12+4}{6+2}\implies \cfrac{16}{8}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=2[x-(-2)] \\\\\\ y+4=2(x+2)\implies y+4=2x+4\implies \blacktriangleright y=2x \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-2%7D~%2C~%5Cstackrel%7By_1%7D%7B-4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B6%7D~%2C~%5Cstackrel%7By_2%7D%7B12%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B12-%28-4%29%7D%7B6-%28-2%29%7D%5Cimplies%20%5Ccfrac%7B12%2B4%7D%7B6%2B2%7D%5Cimplies%20%5Ccfrac%7B16%7D%7B8%7D%5Cimplies%202%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%28-4%29%3D2%5Bx-%28-2%29%5D%20%5C%5C%5C%5C%5C%5C%20y%2B4%3D2%28x%2B2%29%5Cimplies%20y%2B4%3D2x%2B4%5Cimplies%20%5Cblacktriangleright%20y%3D2x%20%5Cblacktriangleleft)
Answer:
-4
Step-by-step explanation:
Slope formula:
m=y2-y1/x2-x1
I will use (-1,10) and (1,2)
2-10/1-(-1)
Which is
-8/2
Divide:
-4
Thus the slope is -4
Hope this helps!
Answer:36 16
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (2, - 4) , thus
y = a(x - 2)² - 4
To find a substitute (3, - 1 ) into the equation
- 1 = a(3 - 2)² - 4 ( add 4 to both sides )
3 = a
Thus
y = 3(x - 2)2 - 4 ← equation in vertex form
= 3(x² - 4x + 4) + 4
= 3x² - 12x + 12 + 4
= 3x² - 12x + 16 ← equation in standard form
with coefficient of x² term = 3
Answer:
I think so
Step-by-step explanation:
here's here's the definition of a parallelogram
"a four-sided plane rectilinear figure with opposite sides parallel."
