Exponential growth would include, A = 20,000(1.08)^t, A=40(30), P=1700(1.07).
Decay would include, A=80(1/2)^t, A= 1600(.8), P=1700(.93)
Hope this helps.
Write and simplify the expression:
3(n-6)+4n
3n-18+4n
7n-18
Solution: 7n-18
I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
8, because the factors of 8 are 1,2,4,8, while the multiples of 8 start with 8,16,24, etc
