Answer:
26 ft square by 13 ft high
Step-by-step explanation:
The tank will have minimum surface area when opposite sides have the same total area as the square bottom. That is, their height is half their width. This makes the tank half a cube. Said cube would have a volume of ...
2·(8788 ft^3) = (26 ft)^3
The square bottom of the tank is 26 ft square, and its height is 13 ft.
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<em>Solution using derivatives</em>
If x is the side length of the square bottom, the height is 8788/x^2 and the area is ...
x^2 + 4x(8788/x^2) = x^2 +35152/x
The derivative of this is zero when area is minimized:
2x -35152/x^2 = 0
x^3 = 17576 = 26^3 . . . . . multiply by x^2/2, add 17576
x = 26
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As the attached graph shows, a graphing calculator can also provide the solution.
Answer:
area of the sector = 360π cm²
Step-by-step explanation:
To calculate the area of the sector, we will follow the steps below;
First write down the formula for calculating the area of a sector.
If angle Ф is measured in degree, then
area of sector = Ф/360 × πr²
but if angle Ф is measured in radians, then
area of sector = 1/2 × r² × Ф
In this case the angle is measured in radiance, hence we will use the second formula
From the question given, radius = 15 cm and angle Ф = 8π/5
area of sector = 1/2 × r² × Ф
=1/2 × 15² × 8π/5
=1/2 ×225 × 8π/5
=360π cm²
area of the sector = 360π cm²
Answer:
A. 5.75
Step-by-step explanation:
11.5/2 = 5.75
Answer:
1.71
Step-by-step explanation:
by using definition of cos
Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7
Double check
24 = 2*(5+7) = 2 *12 = 24
