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2 years ago

How many milliliters are in 5 liters?

Mathematics

1 answer:

blsea [12.9K]2 years ago

5 0

Answer:

There are 5000 mililitres in 5 litres

Therefore option A.

Hope u got the answer............

You might be interested in

The temperature went from -16°F to 7°F. What was the change in temperature?

worty [1.4K]

Answer:

To find this out, we first need to see the change, is it a positive change or a negative change? Well in this case, as the temperature is increasing, we find that the change is positive. The next step we need to do, id that, how much was the change by, we can find this out by finding the absolute value of the difference of -16°F and 7°F

The absolute value means, the operations answer has to be positive, if not then it will become positive.

|-16°F -7°F|

=> |-23°F|

=> 23°F

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

4 0

3 years ago

What type of number is

eimsori [14]

Answer:

A) rational number

Step-by-step explanation:

56 is a rational number because it can be expressed as the quotient of two integers like 56 ÷ 1.

6 0

3 years ago

Read 2 more answers

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Relationship B has a lesser rate than Relationship A. The graph represents Relationship A.

Zinaida [17]

Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a first-quadrant graph showing a ray from the origin through the points (2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis label is Plant growth in inches.

The rate of relationship A is given by the slope of the graph as follows:

$slope= \frac{6-3}{4-2} = \frac{3}{2} =1.5$

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.

For table A.
Time (weeks) 3 6 8 10
Plant growth (in.) 2.25 4.5 6 7.5

$slope= \frac{4.5-2.25}{6-3} = \frac{2.25}{3} =0.75$

For table B.
Time (weeks) 3 6 8 10
Plant growth (in.) 4.8 9.6 12.8 16

 $slope= \frac{9.6-4.8}{6-3} = \frac{4.8}{3} =1.6$

 For tabe C.
Time (weeks) 3 4 6 9
Plant growth (in.) 5.4 7.2 10.8 16.2

 $slope= \frac{7.2-5.4}{4-3} = \frac{1.8}{1} =1.8$

For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9

 $slope= \frac{8.4-6.3}{4-3} = \frac{2.1}{1} =2.1$ 

Therefore, the table that could represent Relationship B is table A.

7 0

3 years ago

Read 2 more answers

List 3 values that would make this inequality true. 65<15x

Romashka-Z-Leto [24]

Anything 5 and up, because when you multiply the by 15, they equal more than 65, making the inequality true.

5 0

3 years ago