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ExtremeBDS [4]
3 years ago
5

2. Give an example of how you use positive and negative numbers in the real world. Be sure to explain the meaning of 0 in your e

xample.
Mathematics
2 answers:
geniusboy [140]3 years ago
7 0
Temperature under 0 Degrees it snows. Also my brain is always right
Ronch [10]3 years ago
7 0
The humidity range today is 0% - 10%. Only if it was that way here lol, the humidity here is actually 97% today, fun. lol
You might be interested in
If a given data point is (1,4) and the line of best fit is y = 1.5x + 3.25, what's the residual value?
Svetlanka [38]

Answer:

The residual value is -0.75

Step-by-step explanation:

we know that  

The residual value is the observed value minus the predicted value.

RESIDUAL VALUE=[OBSERVED VALUE-PREDICTED VALUE]

where

Predicted value.--> the predicted value given the current regression equation

Observed value. --> The observed value for the dependent variable.

in this problem

we have the point (1,4)

so

The observed value is 4

<em>Find the predicted value  for x=1 </em>

y =1.5(1)+3.25=4.75

predicted value is 4.75

so

RESIDUAL VALUE=(4-4.75)=-0.75

4 0
3 years ago
Help BRAINLIEST........
storchak [24]

Answer:

5.52 is the length of wire

8 0
3 years ago
On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

5 0
3 years ago
Please help i will mark branliest
kotegsom [21]

Answer:

C

Step-by-step explanation:

5 0
2 years ago
Solve using the unit rate problems find the constant speed 60 miles in 1.5 hours what is the answer.
kherson [118]
40 miles per hour. if you take 60 divided by 1.5(the speed over time) you get 40mph
7 0
3 years ago
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