Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a
Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b
Looking at this integral we see that the interval is between which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c
Looking at this integral we see that the interval is between which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d
Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
I just did this test the answer is B :-)
Answer:
9(4x+3) :)
Step-by-step explanation:
To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*
Answer:
Step-by-step explanation:
Apply cross product property
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Distribute 5 through the parentheses
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Distribute 6 through the parentheses
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Move 6x to left hand side and change it's sign
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Collect like terms
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Move 30 to right hand side and change it's sign
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Calculate
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Divide both sides of the equation by 9
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Calculate
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Hope I helped!
Best regards!!