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2 years ago

If e || f and a || b, what is the value of y. *

Mathematics

1 answer:

Blizzard [7]2 years ago

3 0

Answer:

y = 90

Step-by-step explanation:

Since, e || f and a || b

Therefore, quadrilateral so formed is a rectangle.

Each angle of a rectangle is right angle.

$\therefore \: y \degree = 90 \degree \\ \\ \huge \red{ \boxed{ \therefore \: y = 90}} \\ \\$

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I need to turn this in! can anyone help ???

elixir [45]

Answer: It's (3,-2)

Step-by-step explanation:

5 0

2 years ago

Solve this system of equations using the substitution method<br>y=x+7<br>-2x-11=y

ryzh [129]

Answer:

x=-6, y=1

Step-by-step explanation:

Let's solve your system by substitution.

y=x+7;−2x−11=y

Step: Solve y=x+7 for y:

y=x+7

Step: Substitute x+7 for y in −2x−11=y:

−2x−11=y

−2x−11=x+7

−2x−11+−x=x+7+−x(Add -x to both sides)

−3x−11=7

−3x−11+11=7+11(Add 11 to both sides)

−3x=18

−3x/ −3 = 18/ −3 (Divide both sides by -3)

x=−6

Step: Substitute−6 for x in y=x+7:

y=x+7

y=−6+7

y=1 (Simplify both sides of the equation)

Answer:

x=−6 and y=1

3 0

2 years ago

Can someone help me which are correct?

taurus [48]

Answer:

Between the first option and the last option.

Step-by-step explanation:

first choice: c, a, d, b, e

last/fourth choice: a,c,d,b,e

7 0

2 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

2 years ago

What is the equation of a circle with a center at (-5,-1) and radius of 6 units?

Karo-lina-s [1.5K]

The second option is right

4 0

2 years ago