Answer:
The length of the square is 6 units.
Step-by-step explanation:
Given that all sides of the square are the same and the area of square formula is A = length×breadth. So let's make x as the sides :
![area = length \times breadth](https://tex.z-dn.net/?f=area%20%3D%20length%20%5Ctimes%20breadth)
![let \: area = 36 \\ let \: sides \: = x](https://tex.z-dn.net/?f=let%20%5C%3A%20area%20%3D%2036%20%5C%5C%20let%20%5C%3A%20sides%20%5C%3A%20%20%3D%20x)
![36 = x \times x](https://tex.z-dn.net/?f=36%20%3D%20x%20%5Ctimes%20x)
![{x}^{2} = 36](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%2036)
![x = ± \sqrt{36}](https://tex.z-dn.net/?f=x%20%3D%20%C2%B1%20%5Csqrt%7B36%7D%20)
![x = 6 \: units](https://tex.z-dn.net/?f=x%20%3D%206%20%5C%3A%20units)
![x = - 6 \: (rejected)](https://tex.z-dn.net/?f=x%20%3D%20%20-%206%20%5C%3A%20%28rejected%29)
Answer:
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Answer:
Yes
Step-by-step explanation:
I think so because it's the same on both sides.
I don't know man. I'm not the best at math :)
Every point in the unit circle is identified either by its coordinates
or by the angle it forms with the x-axis,
.
The trigonometric functions associate with every angle
and the correspondant
coordinates the two values
![\cos(\alpha)=x,\quad\sin(\alpha)=y](https://tex.z-dn.net/?f=%5Ccos%28%5Calpha%29%3Dx%2C%5Cquad%5Csin%28%5Calpha%29%3Dy)
This procedure can be done for every angle
, so you don't have to work with acute angles only.