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3 years ago

Cate and Elena were playing a card game. The stack of cards in the middle had 26 cards in it to begin with.

Mathematics

1 answer:

baherus [9]3 years ago

7 0

Answer:

"Man seeks peace, yet at the same time yearning for war... Those are the two realms belonging solely to man. Thinking of peace whilst spilling blood is something that only humans could do. They're two sides of the same coin... to protect something... another must be sacrificed."

Step-by-step explanation:

You might be interested in

Suppose that in a certain part of the world, in any 50-year period the probability of a major plague is .39, the probability of

antiseptic1488 [7]

<span>Answer: P(famine | plague) = P(famine and plague) / P(plague) = (0.15) / (0.39) = 0.385</span>

4 0

3 years ago

Give first the step you will use to seperate variable and then solve the equation:<br>a)z/3=5/4

luda_lava [24]

Option #1 (and the fastest):
Multiply both sides by 3 to cancel the “divided by 3” on the left side where z is.
z/3 • 3 = 5/4 •3

z = 15/4

Option #2: Cross multiply and then solve for z:
z/3 = 5/4 -> 4z=15

Then divide by 4.
4z/4 = 15/4

z = 15/4

8 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the plate, including t

vredina [299]

You're looking for the extreme values of $x^2+3y^2+13x$ subject to the constraint $x^2+y^2\le1$ .

The target function has partial derivatives (set equal to 0)

$\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2$

$\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0$

so there is only one critical point at $\left(-\dfrac{13}2,0\right)$ . But this point does not fall in the region $x^2+y^2\le1$ . There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of $x^2+y^2\le1$ by

$x=\cos u$

$y=\sin u$

with $0\le u$ . Then $t(x,y)$ can be considered a function of $u$ alone:

$t(x,y)=t(\cos u,\sin u)=T(u)$

$T(u)=\cos^2u+3\sin^2u+13\cos u$

$T(u)=3+13\cos u-2\cos^2u$

$T(u)$ has critical points where $T'(u)=0$ :

$T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0$

$(1)\quad\sin u=0\implies u=0,u=\pi$

$(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4$

but $|\cos u|\le1$ for all $u$ , so this case yields nothing important.

At these critical points, we have temperatures of

$T(0)=14$

$T(\pi)=-12$

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0

3 years ago

The function g(x) is graphed.

sergejj [24]

g(1)=-1 : We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1)=-1 is false.

g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.

So, g(0) =0 is true.

g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.

So, g(4)=-2 is false.

g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1) =1 is true.

g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.

So, g(-1)=1 is true.

g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.

So, g(4)=2 is false.

3 0

3 years ago

(6e-3f-3/4) in a equivalent expression

pashok25 [27]

Answer:

Step-by-step explanation:

(6e-3f-3/4) contains two terms which do not involve fractions and one fractional term (3/4).

We can safely remove the parentheses. Then:

(6e-3f-3/4) => 6e - 3f - 3/4

That is "an equivalent expression."

We could go further and create one equivalent fraction. Multiply the first two terms by 4/4, obtaining:

24e 12f 3 24e - 12f - 3 3(8e - 4f - 1

------ - ------ - ----- => ---------------------- => -------------------

4 4 4 4 4

Other equivalent expressions exist here.

4 0

2 years ago