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xxTIMURxx [149]
3 years ago
15

PLEASE HELP ME I WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

Step-by-step explanation:

realtionship between distance and time is

distance=time/3

a.distance=time/3

129*3=time

387 s =time

Vladimir [108]3 years ago
3 0

Answer:

387

Step-by-step explanation:

129x3=387

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Describe the error Sadie made, and explain how to find the correct answer. (Refer to image)
ki77a [65]

1. Sadie should note that 54a^7b^3\ge 0 and if a\ge 0, then b\ge 0.

2. While simplifying Sadie makes some mistakes (it must be 3^2 instead of 3^3 and she missed the sign of absolute value for b). The right way to find the correct answer is:

\sqrt{54a^7b^3}=\sqrt{3^2\cdot 6\cdot a^2\cdot a^5\cdot b^2\cdot b}  =3\cdot a\cdot |b| \sqrt{6\cdot a^5\cdot b}=3ab\sqrt{6a^5b}.

3. The simpliest expression is 3ab\sqrt{6a^5b} =3ab\sqrt{6\cdot a^2\cdot a^2\cdot a\cdot b} =3a^3b\sqrt{6ab}.

3 0
3 years ago
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Find the three highest whole numbers that satisfy 2(3x+1)⩽ 1/2(2x-5).<br><br><br><br><br>​
Degger [83]

Answer:

-1, -2 ,-3

Step-by-step explanation:

2(3x+1)⩽ 1/2(2x-5)

Distribute

6x+2 ⩽ x-5/2

Subtract x from each side

6x-x +2 ⩽ x-x-5/2

5x +2 ⩽ -5/2

Subtract 2 from each side

5x+2-2 ⩽ -5/2 -2

5x ⩽ -5/2 -4/2

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Divide each side by 5

5x/5 ⩽ -9/2 /5

x ⩽ -9/10

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-1, -2 ,-3

6 0
3 years ago
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What is 4/9÷2/3 show work please!
alexira [117]
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First, apply the rule: a ÷ \frac{b}{c} = a × \frac{c}{b}
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Second, apply the rule: \frac{a}{b} × \frac{c}{d} = \frac{ac}{bd}
\frac{4x3}{9x2}
Third, multiply 4 × 3 to get 12, and 9 × 2 to get 18.
\frac{12}{18}
Fourth, find the GCF of 12 and 18.
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Factors of 18: 1, 2, 3, 6, 9, 18
The GCF is 6.
Fifth, divide the numerator by the GCF. 
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Sixth, divide the denominator by the GCF. 
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Seventh, rewrite your fraction.
\frac{2}{3}

Answer as fraction: \frac{2}{3}
Answer as decimal: 0.6667

7 0
3 years ago
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A rectangle is 2/5 in. long and 1/3 in. wide.what is the area
pashok25 [27]
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4 years ago
What is the maximum vertical distance between the line y = x 30 and the parabola y = x2 for −5 ≤ x ≤ 6?
Arlecino [84]
Set y1=x+30 and y2=x^2, plugged those into the distance formula assuming x=a<span>, 
</span><span>
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</span>All you have to do is to maximize the given quadratic function. I hope that this is the answer that you were looking for and it has helped you.
7 0
3 years ago
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