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4 years ago

What is the simplified form of each expression?

Mathematics

2 answers:

Molodets [167]4 years ago

5 0

1)A

2)A

3)B

4)A

5)C

Hope this helps future kids!!

eimsori [14]4 years ago

3 0

IM pretty sure the answer is
1.A
2.C
3.A
4.D
5.B
:)

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A. 37 b. 62 c. 60 d. 39

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Answer:

39 lang po

Step-by-step explanation:

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3 years ago

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What is the solution to the following equation? −3/5(x−5)+4x=2/5x+12

Damm [24]

Answer:

x=3

Step-by-step explanation:

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3 years ago

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What is the length of a diagonal brace that could be used for a wall 9 feet high and 12 feet long

kolbaska11 [484]

You use the pythagorean theorem to solve this problem. The theorem is a^2+b^2=c^2, where c^2 is the length of the hypotenuse of the triangle, or the side that's the longest and is opposite the right angle of the right triangle. Note that this theorem is applicable because a wall has right angles and it is assumed that the diagonal brace would form a right triangle (the diagonal brace is the hypotenuse). Next, you substitute the values of 9 and 12 for a and b, and then you proceed to solve this algebraically to get c after taking the square roots of both sides of the equation to get c from c^2.

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3 years ago

Find formula of s in terms of a, b, cos(x)

Alecsey [184]

Answer:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

Step-by-step explanation:

We want to find a formula for s in terms of a, b, and cos(x).

Let the point where s intersects AB be D.

Notice that s bisects ∠C. Then by the Angle Bisector Theorem:

$\displaystyle \frac{a}{BD} = \frac{b}{AD}$

We can find BD using the Law of Cosines:

$\displaystyle BD^2 = a^2 + s^2 - 2as \cos x$

Likewise:

$\displaystyle AD^2 = b^2+ s^2 - 2bs \cos x$

From the first equation, cross-multiply:

$bBD = a AD$

And square both sides:

$b^2 BD^2 =a^2 AD^2$

Substitute:

$\displaystyle b^2 \left(a^2 + s^2 - 2as \cos x\right) = a^2 \left(b^2 + s^2 - 2bs \cos x\right)$

Distribute:

$a^2b^2 + b^2s^2 - 2ab^2 s\cos x = a^2b^2 + a^2s^2 - 2a^2 bs\cos x$

Simplify:

$b^2 s^2 - 2ab^2 s \cos x = a^2 s^2 - 2a^2 b s \cos x$

Divide both sides by s (s ≠ 0):

$b^2 s -2ab^2 \cos x = a^2 s - 2a^2 b \cos x$

Isolate s:

$b^2 s - a^2s = -2a^2 b \cos x + 2ab^2 \cos x$

Factor:

$\displaystyle s (b^2 - a^2) = 2ab^2 \cos x - 2a^2 b \cos x$

Therefore:

$\displaystyle s = \frac{2ab^2 \cos x - 2a^2 b \cos x}{b^2- a^2}$

Factor:

$\displaystyle s = \frac{2ab\cos x(b - a)}{(b-a)(b+a)}$

Simplify. Therefore:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

5 0

3 years ago

PLEASE HELP ASAP!!!! m = 10 - 6 / 7 – 8.5

gtnhenbr [62]

For this case we have to define the order of algebraic operations, that the division and multiplication must be done before (from left to right) that the addition and subtraction.

Then, given the following expression:

m = 10-6÷7-8.5

We have to:

$\frac {6} {7} = 0.857$

So, we have:

$m = 10-0.857-8.5$

We must bear in mind that equal signs are added and the same sign is placed, while different signs are subtracted and the sign of the major is placed.

$m = 10-9,357\\m = 0.643$

Answer:

$m = 0.643$

5 0

3 years ago