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2 years ago

I need help please first answer will get brainliest

Mathematics

1 answer:

Masja [62]2 years ago

8 0

Answer:

Mean- 14.5

Median- 15.5

Interquartile Range- 7.5

Step-by-step explanation:

The mean is a type of average. It is the sum (total) of all the values in a set of data.

The median is the middle number in a sorted, ascending or descending, list of numbers.

The interquartile range describes the middle 50% of values when ordered from lowest to highest.

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Find the value of sin T rounded to the nearest hundredth, if necessary.

katovenus [111]

<h3>Answer: 0.6</h3>

========================================

Work Shown:

sin(angle) = opposite/hypotenuse

sin(T) = VU/VT

sin(T) = 3/5

sin(T) = 0.6

6 0

3 years ago

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Divers in a competition are scored by an international panel of judges. The highest and the lowest scores are dropped. The total

Fudgin [204]

From the statements given in the problem, we can say that:

Final Score = (total of the remaining scores) * degree of difficulty * 0.6

Therefore:

97.2 = (total of the remaining scores) * 4.0 * 0.6

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Therefore the judges could have scored which has a total of 40.5

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3 years ago

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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en

GuDViN [60]

Answer:

$P = 0.1447$

Step-by-step explanation:

Given

$n = 7000$ -- total

$d = 180$ --- defective

$r = 6$ --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

$Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}$

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

$Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}$