Answer:
Answer is 
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.


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Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
Square root of 4 is 2
Square root of 9 is 3
7 is between 4 and 9, so its square root is somewhere between 2 and 3, which means the correct answer is between P and Q
The answer is b and c
because they are both parallel to the y-axis
Answer:
The two column proof can be presented as follows;
Statement
Reason
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines
3. ∠9 ≅ ∠11
Transitive property of equality
4. a║b
Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement
Explanation
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11
Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b
Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.