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Stella [2.4K]
3 years ago
7

A squee with one side length represents by an expression is shown below 6(3x+8)+32+12x.

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Side 1 : 6(3x+8)+32+12x

Expression for Side 2 :  (18x+48)+32+12x

Expression for Side 3 :   (18x+12x)+32+48

Expression for Side 4 :    30x+60

<u>Step-by-step explanation:</u>

Here ,Complete question is given in the picture below . Let's calculate side expressions for other 3 sides .

Side 1 : 6(3x+8)+32+12x

Side 2:

Let's simplify 6(3x+8)+32+12x

⇒ 6(3x+8)+32+12x

⇒ (18x+48)+32+12x

Expression for Side 2 :  (18x+48)+32+12x

Side 3:

Let's simplify  (18x+48)+32+12x :

⇒  (18x+48)+32+12x

⇒ (18x+12x)+32+48

Expression for Side 3 :   (18x+12x)+32+48

Side 4:

Let's simplify  (18x+12x)+32+48 :

⇒  (18x+12x)+32+48

⇒ 30x+60

Expression for Side 4 :    30x+60

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Travka [436]

First find the common factor of -30 and 75, which is 15.

Next find the common factors of the variables:

The factors of x$6 is x*x*x*x

Factor for y is y

Factors for Z^3 is z*z*z

Factors for Z^2 is z*z

The GCF would be x^4z^2

Final answer = 15x^4z^2

7 0
3 years ago
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Step-by-step explanation:

a) gradient= y2-y1/x2-x1

gradient of AB:

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gradient of BC:

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3 years ago
(5x to the power of 2 -6x+2)+9x to the power of 2 +10x-7)
xxTIMURxx [149]

Answer:

45x^{4} -4x^{3} -77x^{2} +62x-14

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3 years ago
Assume that when adults with smartphones are randomly​ selected, 52​% use them in meetings or classes. If 14 adult smartphone us
emmasim [6.3K]

The probability that fewer than 4 of then use their smart phones in meetings  or classes is 0.00030243747.

Step-by-step explanation:

Fewer than 4 means ,less than 4 which is any number less than 4 and not including 4. This is 3, 2,1 and 0. So you find the probability that exactly 3 of then use their smart phone, exactly 2 of them use their smart phones, exactly 1 of them use his/her smart phone and none of them.

Given that 52% use smartphones in meetings and classes =0.52

Thus the remaining 48% do not use smartphones in meetings and classes=0.48

For C(14,3) you will have "14 chose 3", number of ways of choosing 3 out of 14'

=(0.52)³ *(0.48)⁹=0.00019018714

For C(14,2) you will have "14 chose 2", number of ways of choosing 2 out of 14

=(0.52)²*(0.48)¹²=0.00004044841

For C(14,1) you will have "14 chose 1", number of ways of choosing 1 out of 14

=(0.52)¹*(0.48)¹³=0.000037337

For  C(14,0) you will have "14 chose 0", number of ways of choosing 0 out of 14

=(0.52)⁰*(0.48)¹⁴=1*0.00003446492=0.00003446492

The probability that fewer than 4 of them use their smartphones in meetings or classes will be

0.00019018714 +0.00004044841+0.000037337+ 0.00003446492=0.00030243747

Learn More

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Keywords : Probability, random variable, binomial distribution

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How many 3/4 foot pieces of string can be cut from a piece of string 4 1/2 feet long
Gnom [1K]
3/4 foot is 9 inches, and 4 1/2 feet is 54 inches, so, 54/9 makes exactly 6 pieces of string. 
8 0
3 years ago
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