Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Since both equations are equal to y, we can just combine them like this:
1/3x-3=-x+5
1/3x=-x+8
4/3x=8 (since x is 1x which is 3/3x)
x=6
Plug x back in:
y=-6+5
y=-1
So x=6 and y=-1
Hope this helped!
Answer:
1.983(10⁴)
Step-by-step explanation:
Since we need to have ones and decimals as proper scientific notation, we have 1.983. Since we need the value of 19830, we need to move the decimal place 4 places to the right, so our exponent is 4.
*I double checked my work this time.
Answer
15 + (-3s) or 15 - 3s
Step-by-step explanation:
-3 times -5 is 15
-3 times s is -3s
