The answer is <span>6 ^3square root of x^4
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</span>![6 x^{3/4} \\ \\ x^{m/n} = \sqrt[n]{ x^{m} } \\ \\ 6 x^{3/4}=6 \sqrt[4]{ x^{3} }](https://tex.z-dn.net/?f=6%20x%5E%7B3%2F4%7D%20%20%5C%5C%20%20%5C%5C%20%0A%20x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7B%20x%5E%7Bm%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A6%20x%5E%7B3%2F4%7D%3D6%20%5Csqrt%5B4%5D%7B%20x%5E%7B3%7D%20%7D%20)
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Calculate the distance between point (5,6) and (7,8)
2 answers:
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Answer:
465 in²
Step-by-step explanation:
square area: A = lw
triangle area: A = lw (or base x height)
= (15)(15) = 225
=
(8)(15) = 60
There is one square and 4 triangles so...
225 + 4(60) = 465 in²
Answer:
slope is -3
Step-by-step explanation:
use slope equation, shown in picture hope this helps
