Answer:
If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.
Explanation:
Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.
- <u>Depolarization</u> occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
- An opening of potassium channels releases this ion to the extracellular space, leading to <u>hyperpolarization</u>.
An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.
On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.
The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.
Learn more:
Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553
In order to improve fat digestion, large fat globules must first be dispersed into smaller droplets in a process called <u>emulsification.</u>
<h3 /><h3>What is emulsification in the digestive system?</h3>
Fat emulsification is the process of increasing the surface area of fats in the small intestine by grouping them into small clusters. Large lipid globules are split up into a number of smaller lipid globules. In the chyme, these tiny globules are widely dispersed rather than aggregating into larger groups. Hydrophobic compounds include lipids. Bile salts, are present in bile and have both hydrophilic and hydrophobic sides.
Due to the fact that lipases can only effectively act on lipids when they are broken down into small aggregates, emulsification is crucial for the digestion of lipids. The lipids are converted into fatty acids and glycerides by lipases.
Learn more about emulsification here:
brainly.com/question/14305593
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The two semilunar valves, the pulmonary and aortic valves, are closed, preventing backflow of blood into the right and left ventricles from the pulmonary trunk on the right and the aorta on the left.
I don't know if this is right but I think B: three times or its probably more than 3 times bc of these hurible people in this world!
