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castortr0y [4]
3 years ago
9

Could someone please help me with this? I would mark you as Brainliest:)

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

a) The table of values represents the ordered pairs formed by the elements of the sequence (a_{i}) (range) and their respective indexes (i) (domain):

i         a_{i}

1         6

2        11

3        16

4        21

5        26

b) The algebraic expression for the general term of the sequence is a(i) = 6 + 5\cdot (i - 1).

c) The 25th term in the sequence is 126.

Step-by-step explanation:

a) Make a table of values for the sequence 6, 11, 16, 21, 26, ...

The table of values represents the ordered pairs formed by the elements of the sequence (a_{i}) (range) and their respective indexes (i) (domain):

i         a_{i}

1         6

2        11

3        16

4        21

5        26

b) Based on the table of values, we notice a constant difference between two consecutive elements of the sequence, a characteristic of arithmetic series, whose form is:

a(i) = a_{1} + r\cdot (i - 1) (1)

Where:

a_{1} - First element of the sequence.

r - Arithmetic difference.

i - Index.

If we know that a_{1} = 6 and r = 5, then the algebraic expression for the general term of the sequence is:

a(i) = 6 + 5\cdot (i - 1)

c) If we know that a(i) = 6 + 5\cdot (i - 1) and i = 25, then the 25th term in the sequence is:

a(25) = 6 + 5\cdot (25 - 1)

a(25) = 126

The 25th term in the sequence is 126.

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Answer:

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Step-by-step explanation:

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3 years ago
Factor the expression given below. Write each factor as a polynomial in
bezimeni [28]

Answer:

3(343=72y)

Step-by-step explanation:

343x3=1029

1029+216y

both divisible by 3

3(343=72y)

6 0
3 years ago
Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0
3 years ago
20 points! HELP AND ILL MARK BRAINLIEST!
Keith_Richards [23]

you do 77 divided by 14 you get 5.5 so the greatest number of teams is 5.

4 0
3 years ago
( 16.9 - 5.47 ) x 7.09 plzz i want with full solution
Mila [183]

Answer:

81.03

Step-by-step explanation:

(16.9-5.47)×7.09

(11.43)×7.09

81.0387

OR

81.03

HOPE THIS HELPS YOU

8 0
3 years ago
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