All categories

2 years ago

1. 7a x 8 =168 2. 7+ 2a =23 3. 6c + 8c =28

Mathematics

2 answers:

3241004551 [841]2 years ago

7 0

Answer:

1. a = 3

2. a = 8

3. c = 2

Step-by-step explanation:

7a x 8 = 168

56a = 168 <-- 7a x 8 =56
(56a)/56 = 168/56 <-- divide both sides by 56
a = 3

7 + 2a = 23

(7 + 2a) - 7 = 23 - 7 <-- subtract 7 from both sides
2a = 16
(2a) / 2 = 16/2 <-- divide both sides by 2
a = 2

6c + 8c = 28

14c = 28 <-- 6c + 8c = 14c
c = 2 <-- divide both sides by 14

EastWind [94]2 years ago

6 0

Answer:

first is 3, then 8, then it's 2

You might be interested in

A recent poll found that 35% of those surveyed are worried about aggressive drivers on the road. If three people are selected at

Ugo [173]

The probability that all three people surveyed is an independent probability and the calculated probability is 0.1225

The probability a surveyed driver is worried = 35%

P(worried) = 0.35

Number of people surveyed = 3

Since the probability of being worried is independent ;

Probability = P(A) × P(B) × P(C)

The probability that all 3 surveyed are worried :

P(worried) × P(worried) × P(worried)
(0.35 × 0.35 × 0.35) = 0.1225

Therefore, the probability that all three people surveyed are worried is : 0.1225

Learn more : brainly.com/question/18153040

5 0

2 years ago

Which side of XYZ is the longest? A. xy B. xz C. yz D. cannot be determined

Eddi Din [679]

Answer:

the answer is x because its small

4 0

3 years ago

Which list puts the following things in correct order from smallest to largest?

slega [8]

Answer:

A. "hope this helps"

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

Kay [80]

Answer: -3a^5b^6

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

3 years ago