<span>The sum of the measures of the interior angles of a polygon with n sides is (n – 2)180.The measure of each interior angle of an equiangular n-gon is.<span>If you count one exterior angle at each vertex, the sum of the measures of the exterior angles of a polygon is always 360°</span></span>
Answer:
4
Step-by-step explanation:
8% is also 8/100. This would be true for all percents 0 to 100%. If it were 42% it can be written as 42/100.
So, 8% is 8/100. If you want to find 8/100 of 50 multiply them.
8/100 * 50/1 = (8*50) /100
400/100 = 4
Answer:
197
Step-by-step explanation:
Divide 1640 by 25
1640/25=65
Then multiply 65 and 3
65x3=197
Average of 2 numbers is 40
so total = 2 x 40 = 80
300 - 80 = 220
average of remaining 10 numbers = 220/10 = 22
answer
B) 22
Answer:
They'll reach the same population in approximately 113.24 years.
Step-by-step explanation:
Since both population grows at an exponential rate, then their population over the years can be found as:
For the city of Anvil:
For the city of Brinker:
We need to find the value of "t" that satisfies:
![\text{population brinker}(t) = \text{population anvil}(t)\\21000*(1.04)^t = 7000*(1.05)^t\\ln[21000*(1.04)^t] = ln[7000*(1.05)^t]\\ln(21000) + t*ln(1.04) = ln(7000) + t*ln(1.05)\\9.952 + t*0.039 = 8.8536 + t*0.0487\\t*0.0487 - t*0.039 = 9.952 - 8.8536\\t*0.0097 = 1.0984\\t = \frac{1.0984}{0.0097}\\t = 113.24](https://tex.z-dn.net/?f=%5Ctext%7Bpopulation%20brinker%7D%28t%29%20%3D%20%5Ctext%7Bpopulation%20anvil%7D%28t%29%5C%5C21000%2A%281.04%29%5Et%20%3D%207000%2A%281.05%29%5Et%5C%5Cln%5B21000%2A%281.04%29%5Et%5D%20%3D%20ln%5B7000%2A%281.05%29%5Et%5D%5C%5Cln%2821000%29%20%2B%20t%2Aln%281.04%29%20%3D%20ln%287000%29%20%2B%20t%2Aln%281.05%29%5C%5C9.952%20%2B%20t%2A0.039%20%3D%208.8536%20%2B%20t%2A0.0487%5C%5Ct%2A0.0487%20-%20t%2A0.039%20%3D%209.952%20-%208.8536%5C%5Ct%2A0.0097%20%3D%201.0984%5C%5Ct%20%3D%20%5Cfrac%7B1.0984%7D%7B0.0097%7D%5C%5Ct%20%3D%20113.24)
They'll reach the same population in approximately 113.24 years.
