3 years ago

PLEASE LOOK AT THE ATTACHMENT!!

1 answer:

5 0

Answer:

mkay

Step-by-step explanation:

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morpeh [17]

The answer is the bottom !hope this helps!

7 0

3 years ago

Lunna [17]

I believe the two fractions are the numbers they all have in common.

6 0

4 years ago

fredd [130]

Answer:

its easy solve it with calculator

Step-by-step explanation:

8 0

3 years ago

avanturin [10]

Answer:

B. No

$Cos \ \theta\neq Cos (90-\theta)\textdegree$

Step-by-step explanation:

-A right angle triangle has two complimentary acute angles and one right angle.

- $\theta$ is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.

-Complimentary angles add up to 90º.

#For complimentary angles:

$Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree$

The two acute angles cannot have the same Cosine value.

Hence, she's not correct.

5 0

3 years ago

scoundrel [369]

Answer: its 180

Step-by-step explanation: length times width is the area. 15 times 12 is 180

5 0

3 years ago