Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
Microbiology studies organisms too small to be seen with the naked eye
Answer:
Divergent plate boundaries because the separating of the tectonic plates allows for the lava to push its way through the rift and escape to Earth's surface.
Answer:
The main role of carbonic anhydrase in humans is to catalyze the conversion of carbon dioxide to carbonic acid and back again. However, it can also help with CO2 transport in the blood which in turn helps respiration. It can even function in the formation of hydrochloric acid by the stomach.
Explanation:
<span>The juxtaglomerular apparatus is a structure (formed by the distal convoluted tubule and the glomerular afferent arteriole) with the function in the regulation of blood pressure and the filtration rate of the glomerulus. Its primary components are:
</span> <span><span>· </span>the macula densa- specialized epithelial cells in the distal convoluted tubule (detect Na concentration),
</span> <span><span>· </span>juxtaglomerular cells- formed from the smooth muscle cells of the afferent arteriole (secrete renin),</span>
<span><span>· </span>extraglomerular mesangial cells (lacis cells)-unknown function.</span> <span> </span>
