Answer:
50%
Explanation:
This question involves a gene coding for eye color in humans. The allele for brown eyes (B) are dominant to blue eyes (b). This means that blue-eyed individual will possess genotype: bb.
According to this question, a blue-eyed man (bb) has children with a brown-eyed woman (B_) whose mother has blue eyes (bb). Since the mother of the brown-eyed woman has a blue eye, this means that the woman will be heterozygous for brown eye (Bb).
Hence, the parents in this question will cross as follows: blue eyed man (bb) × brown-eyed woman (Bb). The offspring/children will have the following genotypes (see attached punnet square); Bb, Bb, bb, bb.
Based on the question, 2/4 = 1/2 of the children will be heterozygous for the eye color trait. That is, ½ × 100 = 50%.
Diversifying selection, describes changes in population genetics in which extreme values for a trait are favored over intermediate values. The variance of the trait increases and the population is divided into two distinct groups. In the above question an example of diversifying selection is A population of moths with white and grey forms lives in a forest containing trees with light and dark bark.
It needs a C) host cell in order to reproduce
The measurement of the force of gravity pulling down an object is called weight, which is basically what you see when you step on a scale.