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3 years ago

Consider the quadratic expression given below.

1 answer:

7 0

Factor out 4
4(x^2 + 2x - 15)

to factor the equation inside the parenthesis, find two numbers that multiply to -15 and add to 2
those numbers are: 5 and -3

the answer is: 4(x+5)(x-3)

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a student showed the steps below while solving the equation 14=log5(2x-3) by graphing. which step did the student make the 1sr e

mixer [17]

Answer:

$x= \frac{5^{14}+3}{2}$

Step-by-step explanation:

The correct steps to solve the equation are:

$14=log_5(2x-5)$

$5^{14}=5^{log_5(2x-3)}$

Because $a^{log_am}=m$

So, solving we get:

$5^{14}=2x-3$

Sum 3 on every side:

$5^{14}+3=2x-3+3\\5^{14}+3=2x$

Dividing by 2 into both sides:

$\frac{5^{14}+3}{2}=\frac{2x}{2}\\\frac{5^{14}+3}{2}=x$

So, the answer is $x= \frac{5^{14}+3}{2}$

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3 years ago

In column C, there are too many numbers after the decimal place. Karl does not need this level of detail as it is distracting fr

Gemiola [76]

Round his data to 2 decimal places

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3 years ago

This supply graph shows the supply of video games

Andrews [41]

The correct answer is 300

8 0

3 years ago

Read 2 more answers

Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares:

$x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)$

And if you're working over the field of complex numbers, you can go even further. For instance,

$x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)$

But I think you'd be fine stopping at the first result,

$x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}$

6 0

3 years ago

Paula wants to buy new carpet for her bedroom. The floor is in the shape of a rectangle. Its length is 16 feet and its width is

irga5000 [103]

Answer: 1408

Step-by-step explanation:

You are finding the area of the rectangle (length times width). You are going to multiply 16 and 11, which equals 176. You take the area of the carpet and multiply it by how much it costs($8.00). The answer would be $1408.00

3 0

3 years ago