Answers:
CB = 14
GF = 8
FB = 9
EF is parallel to CB
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Explanations:
Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14
For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.
FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length
EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.
I would think that it would be A.... I am an expert but, only in 8th, so I would double check.
Answer:
b. 6 cm
Step-by-step explanation:
Q is the midpoint of PR, so QR = PR/2 = (12 cm)/2 = 6 cm
Answer:
9 = n
Step-by-step explanation:
12 = 6(n – 7)
Divide by 6 on both sides
12/6 = 6/6(n – 7)
2 = n-7
Add 7 to each side
2+7 = n-7+7
9 = n
Step-by-step explanation:
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