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2 years ago

Solve this system of equations by graphing. First graph the equations, and then type the solution. y= x+3 y=2x

Mathematics

1 answer:

Yuliya22 [10]2 years ago

3 0

Answer:

(3,6)

Step-by-step explanation:

Y=X+3

Y=X2

X+3=2X

X-2X= -3

-x=-3

x=3

then Y=2X

Y=2×3

Y=6

(3,6)

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3 years ago

A truck costs 80,000. it depreviates in value 6,000 per year

Lilit [14]

Answer:in one year it will be 74000

Step-by-step explanation:

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3 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Nicky is considering two different companies for textbook rentals. For

maks197457 [2]

Answer:

if youre answer has to be a whole number it would be 3 otherwise it would be x<4 ( so anything less than 4 )

Step-by-step explanation:

so because we are trying to find which company is less, we need to set up in inequality.

so first lets do company A

because 15 is our reoccuring fee, its going to be the coeifficient

so the equation would be

A - 15x + 20

now lets do company B

because it only 20 every month we dont need to have a constant which means the equation for B would be

B - 20x

so lets put it all together

15x + 20 > 20x ( remember our B side has to be less )

now lets solve it

20 > 5x

we know that if x = 4 then the two would be equal, which means our answer would have to be 3 months.

now always check your work.

15 (3) + 20 = 65

20(3) = 60

3 0

3 years ago

1. What is the solution to the system below? x+y=5 1x- y=3

Alika [10]

Answer:

(4,1)

Step-by-step explanation:

x+y=5

x- y=3

Add the equations together to eliminate y

x+y=5

x- y=3

--------------------

2x = 8

Divide each side by 2

2x/2 = 8/2

x = 4

Now we can find y

x+y = 5

4+y = 5

Subtract 4 from each side

4+y-4 = 5-4

y =1

5 0

2 years ago