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3 years ago

½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓ simplify IF NEEDED

Mathematics

1 answer:

Volgvan3 years ago

4 0

Answer:

$( \frac{1}{2} x + 1 \frac{2}{3} ) - (1 \frac{1}{2} x - 1 \frac{1}{3} ) \\ = ( \frac{1}{2} - \frac{3}{2} )x + ( \frac{5}{3} + \frac{4}{3} ) \\ = \frac{ - 2}{2} x + \frac{9}{3} \\ = - x + 3 \\ = 3 - x$

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Factor LaTeX: 7v^2+31v+12

bazaltina [42]

Answer:

(7v +3 ) ( v + 4 )

Step-by-step explanation:

7v^2+31v+12

(7v + ) ( v + )

12 = 1*12

2*6

3*4

7* 4 + 3 = 31

(7v +3 ) ( v + 4 )

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3 years ago

Multiple fraction them simply 2/50 x5/18

Vika [28.1K]

2 x 5/ 50 x 18

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3 years ago

Describe the relationship between the terms in each arithmetic sequence. Then write the next three terms in each sequence.

aliya0001 [1]

Answer:

Answer b)

Step-by-step explanation:

In the sequence 0, 5, 10, 15,...

5 is added to each term in order to get the next one. Therefore the next three terms would be; 20, 25, 30.

This agrees with answer b) in the list of possible answers.

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3 years ago

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.

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3 years ago

56 = 34x +24 answer please

Mamont248 [21]

Answer: x=16/17

Step-by-step explanation: 56=34x+24 34x+24−24=56−24 34x/34=32/34/2/2

x=16/17

3 0

3 years ago

Read 2 more answers