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Mamont248 [21]
3 years ago
12

½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓ simplify IF NEEDED

Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:

( \frac{1}{2} x + 1 \frac{2}{3} ) - (1 \frac{1}{2} x - 1 \frac{1}{3} ) \\  = ( \frac{1}{2}  -  \frac{3}{2} )x  +  ( \frac{5}{3}  +  \frac{4}{3} ) \\  =  \frac{ - 2}{2} x +  \frac{9}{3}  \\  =  - x + 3 \\  = 3 - x

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Factor <br><br> LaTeX: 7v^2+31v+12
bazaltina [42]

Answer:

(7v +3 ) ( v    + 4  )

Step-by-step explanation:

7v^2+31v+12

(7v + ) ( v    +   )

12 = 1*12

       2*6

       3*4

7* 4 + 3 = 31

(7v +3 ) ( v    + 4  )

6 0
3 years ago
Multiple fraction them simply 2/50 x5/18
Vika [28.1K]
2 x 5/ 50 x 18

10 / 900

Divide both by 10

1/90
5 0
3 years ago
Describe the relationship between the terms in each arithmetic sequence. Then write the next three terms in each sequence.
aliya0001 [1]

Answer:

Answer b)

Step-by-step explanation:

In the sequence 0, 5, 10, 15,...

5 is added to each term in order to get the next one. Therefore the next three terms would be; 20, 25, 30.

This agrees with answer b) in the list of possible answers.

3 0
3 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
3 years ago
56 = 34x +24 answer please
Mamont248 [21]

Answer: x=16/17

Step-by-step explanation: 56=34x+24 34x+24−24=56−24 34x/34=32/34/2/2

x=16/17

3 0
3 years ago
Read 2 more answers
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