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pishuonlain [190]
3 years ago
14

Solve for x. .......................

Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0

Answer: For both 3x+1 and 7x-1 is There are no like terms.

I don’t know if you want me to solve because I did “Answer: There are no like terms.” or how you want it because the picture you show it confusing

Step-by-step explanation: Hope this help :D

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What is the simplest form of 3/27a2b7?
krok68 [10]

Answer:

the solution is A

Step-by-step explanation:

\sqrt[3]{27a^{3}b^{7}  } \\

\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}

4 0
3 years ago
Read 2 more answers
Use the Intermediate Value Theorem to show that the polynomial has a real zero between -4 and -1
hjlf
The answer is A
F (-4)=-23 < 0
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8 0
4 years ago
Please help me ill give brainliest ty &lt;3
Sati [7]
The other endpoint (x,y)
(X+18)/2 = 16 then x=14
(Y-18)/2 = -16 then y=-14
6 0
3 years ago
How many x-intercepts would the function shown below have? <br> F(x) =x^2 (x^2+9) (x^2-3) (5x+1) ^2
-BARSIC- [3]

Step-by-step explanation:

step 1. x intercepts are where y = 0

step 2. y = 0 when factors are equal to zero

step 3. the x intercepts are 0, sqr(3), -sqrt(3), -1/5

step 4. answer: 4.

6 0
3 years ago
Help explain an show work thank you so much!
Dominik [7]

5 is (D)...…………………okay

7 0
3 years ago
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