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gavmur [86]
3 years ago
14

line passes through points (5, 8) and (10, 5). Line b is parallel to line a. what is the slope of line b?? ​

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

-3/5

Step-by-step explanation:

Let's go from the point (5, 8) to the point (10, 5).  We can see immediately that x (the 'run') increases by 5 and y (the 'rise') decreases by 3.  Thus, the slope of the line connecting these two points is m = rise/run = -3/5.

Both of these lines have the slope -3/5, given that they are parallel lines.

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Vsevolod [243]
We know that, in the US, the average mile per gallon was 25 mpg in 2015. Since we don't have the mile per gallon of the car in our problem, we are going to use that average.
For our first situation, <span>drive 0.3 miles to fill up for $3.59 per gallon:
</span>\frac{25miles-----\ \textgreater \ 1gallon}{0.3miles-----\ \textgreater \ xgallons}
\frac{25}{0.3} = \frac{1}{x}
x= \frac{(1)(0.3)}{25}
x=0.012
<span>We just proved that in our trip, we used 0.012 gallon, and at $3.59 per gallon; we will pay  (0.012)(3.59)=$0.04 for that gasoline.

For our second situation, </span><span>drive 1.2 miles to fill up for $3.41 per gallon:
</span>\frac{25miles-----\ \textgreater \ 1gallon}{1.2miles-----\ \textgreater \ xgallons}
\frac{25}{1.2} = \frac{1}{x}
x= \frac{(1)(1.2)}{25}
x=0.048
We just proved that in our trip, we used 0.048 gallon, and at $3.41 per gallon; we will pay  (0.048)(3.41)=$0.16 for that gasoline.

We can conclude that is much better to drive 0.3 miles to fill up for $3.59 per gallon than drive <span>1.2 miles to fill up for $3.41 per gallon.</span>
8 0
3 years ago
I need some help, yes this is a repost soz.
Alinara [238K]

Answer:

Whats the question ;-;

Step-by-step explanation:

6 0
3 years ago
What is 24 percent of 289
kap26 [50]
It would be: 289*24/100 = 6936/100 = 69.36
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3 years ago
If the diameter is 12 miles. What is the circles circumference?​
Basile [38]

C≈37.7mi

I hope it's helpful

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3 years ago
Which expression is equivalent to (8^2)^-4
xz_007 [3.2K]

Answer:

C: \frac{1}{8*8*8*8*8*8*8*8}

Step-by-step explanation:

a^{-n} = \frac{1}{a^n}

Since a = 8^2 :

(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}

Since n = 4 :

(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}

6 0
3 years ago
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