3 years ago

I. Label the parts

Mathematics

2 answers:

Arlecino [84]3 years ago

8 0

Step-by-step explanation:

Question number 1 The part is 23 and the whole is 35 and the percent is 66%.

Question number 2 is The part is 20 and the whole is 32 and the percent is 62.5%.

Question number 3 is 41 is 82% of 50.

Question number 4 is 3 is 6%of 18.

Question number 5 is 14 is 28% of 50.

coldgirl [10]3 years ago

6 0

1. the part: 23 the whole: 35 the percent: 66%
2. part: 20 the whole: 32 the percent: 62.5%

You might be interested in

kim practices soccer each day. she made a chart of the number of shots she made and the goals she scored. find the equation that

Sedaia [141]

Answer:4x

Step-by-step explanation:

8 0

2 years ago

A teacher has assigned numbers 1-8 to eight students in a classroom. The numbers of all the students are put in a basket. The te

iren2701 [21]

Answer:

There is a 1/64 possibility.

Step-by-step explanation:

Since the probability of selecting student 1's number is 1/8 and then replacing it leaves us with still 8 numbers to choose from, so student 8's probability of being selected is also 1/8. Multiplying these two gives P=1/64, since (1/8)^2 = 1/64.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Olivia's goal is to complete 200 sit ups Right now she is up to 50 sit ups What percentage of her goal has she reached?

Lelechka [254]

She has reached 25 percent of her goal

8 0

3 years ago

A. write an equation that relates a and b when a = 4 when b = 24

tatiyna

Answer:

a + b = 28

b = 31

Step-by-step explanation:

i hope it's correct but I am not sure tho :)

3 0

3 years ago

The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).

garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

$f(x)=x^2+6x+3$

$g(x)=f(x-2)$

$g(x)=(x-2)^2+6(x-2)+3$ (Replaced x in f with (x-2))

$g(x)=x^2-4x+4+6x-12+3$ (Used $(x+b)^2=x^2+2bx+b^2$ and distributive property)

$g(x)=x^2-4x+6x+4-12+3$ (Gathered like terms)

$g(x)=x^2+2x-5$ (Simplified)

The vertex of a parabola occurs at $(\frac{-b}{2a},g(\frac{-b}{2a})$ .

Let's find $\frac{-b}{2a}$ first.

$\frac{-2}{2(1)}=-1$

Now we can obtain $g(\frac{-b}{2a})$ which is $g(-1)$ in this case:

$g(x)=x^2+2x-5$

$g(-1)=(-1)^2+2(-1)-5$

$g(-1)=1-2-5$

$g(-1)=-1-5$

$g(-1)=-6$ .

The vertex is (-1,-6).

6 0

3 years ago