What is the vertex of the absolute function defined by f(x)=|x-7|+1

Mathematics

2 answers:

lukranit [14]3 years ago

6 0

Answer:

Step-by-step explanation:

x-1 = 1

x=2

x-1=-1

x=-2

kati45 [8]3 years ago

4 0

The answer is for the vertex is (7,1)

You might be interested in

Someone help 6th grade math i will give brainliest to the first person

TiliK225 [7]

Answer:

(2x+7t) (5x-3p)

Step-by-step explanation:

4 0

3 years ago

Say that the economy is in a recession, causing vehicle prices to drop by eight percent. If your car was previously worth $25,29

qaws [65]

Answer:

$23,271

Step-by-step explanation:

i took the same test on edg

8 0

3 years ago

Read 2 more answers

Which simplifications of the powers of i are correct? There may be more than one correct answer.

fredd [130]

$\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark$

$\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes$