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Nady [450]
2 years ago
11

What is the equation of the linear function in standard form that has a slope of -4 and a y-intercept of -5?

Mathematics
1 answer:
Anastaziya [24]2 years ago
6 0

Step-by-step explanation:

y-Intercept = (0 , -5)

Slope / m = -4

y - y1 = m(x - x1)

y + 5 = -4(x - 0)

y = -4x - 5 → Equation

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So a man goes to sleep at 8 am and wakes up on the following day and wakes up at 1 am. can you tell me what happened?
Nata [24]

Answer:

He was on an airplane.

Step-by-step explanation:

Hope I helped!

Please mark Brainliest!!!

5 0
2 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
What are the similarities and differences between comparing whole numbers and decimals
Helga [31]
There both types of numbers but a whole number is a number with no exponents or decimals, but decimals are like a broken un half whole number
3 0
3 years ago
Read 2 more answers
Plz help plz plz help helpe ​
jeka57 [31]

Answer:

-2 1/5, -1 2/5, 1/5, |-3/5|, |-1 1/5| ,|-2 2/5|

Step-by-step explanation:

Absolute value means take the positive value

-2 1/5

|-1 1/5| = 1 1/5

|-2 2/5| = 2 2/5

1/5

|-3/5| = 3/5

-1 2/5

We want the numbers from smallest to largest

The most negative is

-2 1/5, -1 2/5

Then to the fractions

1/5, |-3/5|

Then the positive numbers

|-1 1/5| ,|-2 2/5|

3 0
3 years ago
Rectangle ABCD is similar to rectangle RSTU .
Alenkasestr [34]

Answer:

The scale factor of a dilation from ABCD to RSTU is \frac{1}{2}

Step-by-step explanation:

We know that the rectangle ABCD is similar to rectangle RSTU.

Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS

Working with the lengths of the sides :

DC.(Scale factor) = UT

AB.(Scale factor) = RS

Replacing with the values of the lengths (Scale factor : SF) :

DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

Notice that the scale factor is dimensionless.

We can verify this result with the sides AD and BC :

AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

The scale factor (SF) is \frac{1}{2}

7 0
3 years ago
Read 2 more answers
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