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alexandr1967 [171]
3 years ago
5

Evaluate 27x squared - 42x + 12

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0
The answer is -42x+741.
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Find n.<br> 12/18=n/36<br> n=_____
Vaselesa [24]
18 x 2 = 36
n = 12 x 2
n = 24
3 0
3 years ago
Find the measures of the indicated angles in circle O. Which statement is NOT true? (The figure is not drawn to scale.)
Goshia [24]

Answer:

c = 73

Step-by-step explanation:

We know an intercepted angle from 2 point in an arc of a circle (at the other circumference' side) is HALF of the angle measure of the arc. And if the intercepted angle is at the CENTER, its measure is SAME as the measure of the intercepted arc.

The angle 53 is given only, so we look from the 2 points in the arc of this angle. We can see that a also originates from this arc, so a is equal to 53.

B also originates from this arc, but at the center, so b = DOUBLE of 53 = 106. b = 106

b and c are supplementary (they fall in a line and thus add up to 180 degrees). So

106 + c = 180

c = 180 - 106 = 74

<em>Looking at the answer choices, c is given as 73, which is wrong! Hence, </em><em>last statement is not true.</em>

4 0
3 years ago
15 BE The plant Bryan was growing for the science fair was 1.25 feet tall when he planted it. At the end of 4 weeks, it had grow
notsponge [240]

Step-by-step explanation

C.

6 0
3 years ago
Evaluate the following expressions given x=6 and y=-3
Nana76 [90]

a.

\purple{5 \times 6 - 4 \times ( - 3)}

= 30 + 12

\blue{ =  \boxed{42}}

b.

\purple{ {6}^{2}  +  \frac{6}{ - 3} }

= 36 - 2

\blue{ =  \boxed{34}}

c.

\purple{(6 - 5 {)}^{3}  +  {( - 3)}^{2} }

=  {1}^{3} + 9

= 1 + 9

\blue{ =  \boxed{10}}

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
7 0
3 years ago
X and y are in direct proportion, when x is 8, y is 12. Which of the following is not a
Nat2105 [25]

Answer:

d.

Step-by-step explanation:

if x varies directly as y,

x = ky

8 = 12k

12k = 8

k = 8/ 12

k = 2/3,

x = 2/3 y

now substitute the value of any of the numbers of each pair, and check if it works:

for e.g, find x when y = 15

x = 2/3y

x = 2/3 × 15

x = 10

since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .

ii) x = 2/3y

x = 2/3 × 3, when y = 3

x = 2

hence, this is also a possible pair of x and y values.

iii) x = 2/3y

x = 2/3 × 9 when y = 9

x = 6

again, a possible pair of x and y values.

iv) x = 2/3y

x = 2/3 × 20 when y = 20

x = 40/3

here, when y = 20, x is not 15. it is 40/3.

thus, it can be determined that this is not a possible pair of x and y values.

please try to understand and have a great day!

8 0
2 years ago
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