Can someone please help me answer this because it is due in a couple of minutes. Please help
1 answer:
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Answer:
Explanation:
Since, there are two possible outcomes for every toss (head or tail), the sample space for<em> a coin tossed 8 times</em> is 2×2×2×2×2×2×2×2 = 2⁸ = 256.
<em>Landing on heads all 8 times</em> is just one of the possible outcomes: HHHHHHHH ⇒ 1.
Hence, the <em>probability </em>is calculated from its own definition:
Probability = number of favorable outcomes / number of possible outcomes
The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P, , where
. The slope of the secant line through P and Q is given by the difference quotient,
where we are allowed to simplify because .
Then the equation of the secant line is
Taking the limit as , we have
so the slope of the line tangent to the curve at P as slope 2.
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We can verify this with differentiation. Taking the derivative, we get
and at , we get a slope of
, as expected.