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3 years ago

Hey can you please help me posted picture of question

Mathematics

2 answers:

ruslelena [56]3 years ago

5 0

Answer:
Two

Explanation:
The solution of a system of equations is defined as the values which satisfies both equations.

Graphically, the solutions are represented by the points of intersection between the two equtaions.

In the given graph, we have a circle and a line, we can note that these two intersect in two points.

This means that the system has two solutions

Hope this helps :)

dimaraw [331]3 years ago

4 0

Points of intersection are solution set. Answer is 2.

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John is a runner. He runs the 100m sprint in 10x6s. What speed did he travel at? (in m/s)

kykrilka [37]

Step-by-step explanation:

10x6s=60

100 divided by 60

=5/3 m/s OR 1.6666666666666666666 m/s

7 0

3 years ago

Plz help mee ;-; .................

forsale [732]

4X+60=640
4X=640-60
4X=580
X=580/4=145

8 0

3 years ago

Corinne bought 5 bags of chips and 4 jars of dipping sauce for $21.82. At the same prices, Ginger bought 4 bags of chips and 3 j

mr_godi [17]

Answer:

The price of one jar of dipping sauce is $2.98

Step-by-step explanation:

Let

x ----> the price of one bag of chip

y ----> the price of one jar of dipping sauce

we know that

Corinne

$5x+4y=21.82$ ----> equation A

Ginger

$4x+3y=16.86$ ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (1.98,2.98)

see the attached figure

therefore

The price of one bag of chip is $1.98

The price of one jar of dipping sauce is $2.98

7 0

3 years ago

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago

17m-12n-1 + 4-13m-12n

kvasek [131]

Answer: 4m+-24n+3

This could be or you can write it like 4m-24n+3. And that’s the answer depends on what your doing. And you can’t simply anymore so that’s the best answer.

5 0

3 years ago

Read 2 more answers