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Igoryamba
3 years ago
14

Find the x-intercept for the line represented by this equation.

Mathematics
1 answer:
saul85 [17]3 years ago
8 0

Answer:

I think the answer is A to you answer

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Is 4(5a-8)+2a equivalent to 12a-6
dem82 [27]
No, it would end up being 20a-32 which is not equivalent to 12a-6
8 0
3 years ago
Read 2 more answers
What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.
schepotkina [342]

Answer:

2

Step-by-step explanation:

The given equation of line is

3x+6y=-18

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

3x+6y+18=0      ...(i)

If a line is defined as ax+bx+c=0, then the slope of the line is  

m=-\dfrac{a}{b}

In equation (i), a=3, b=6 and c=18. So, slope of the line is

m_1=-\dfrac{3}{6}=-\dfrac{1}{2}

Let m_2 be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

m_1\cdot m_2=-1

(-\dfrac{1}{2})\cdot m_2=-1

Multiply both sides by -2.

m_2=2

Therefore, the slope of perpendicular line is 2.

6 0
3 years ago
Simplify<br> Enter answer in box:
lesantik [10]

(3/5 + -1/4)/(7/10)

get a common denominator of 20

3/5 * 4/4 =12/20

-1/4 * 5/5 = -5/20

7/10 *2/2 = 17/20

replace

(12/20 - 5/20)/(14/20)

add the top

(7/20)/(14/20)

copy dot flip

7/20 * 20/14

7/14

1/2


7 0
3 years ago
Read 2 more answers
17 points<br><br>please help me fill it xx
SSSSS [86.1K]
For the very last part, a is 29 and b is 45.
8 0
3 years ago
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How many angles between 0° and 360° have a tangent of<br> of 2/3?
slega [8]

Answer:

  2

Step-by-step explanation:

The tangent is positive in quadrants I and III. There are two angles with that tangent value:

  33.96° and 213.69°

5 0
2 years ago
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