You group the like terms together
6a+2a=24-8
8a=16
a=16÷8
a=2
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz
The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz
2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz
3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz
B) The answers are:
the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz
The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz
2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz
3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
Question 1)
there’s 180 degrees in a triangle
70 + 70 = 140
180 - 140= 40
A= 40
question 2)
there’s only one line of symmetry, down the middle
Answer:
-4 seconds
Step-by-step explanation:
The question says he lost 8 seconds off the leader for each of the 3 pit stops that he made
8 x 3 = 24
This means that 24 seconds was lost.
If 10 seconds were gained for the next 2 pit stops, the driver gained a total of
2 x 10 = 20seconds
The amount of time he is off leader =
20 -24
= -4 seconds
We have it that -4 seconds represents time he is off the leader.
Thank you!
I got that x equals -3.809523 (repeating)