You could do this with two weighings assuming its a two pan balance - (1) place three balls on each side - if they balance out then its the remaining three that has abnormal ball (2) out of that group, place one ball on each side - if balances it out, the abnormal ball is the remaining one.
If the weighing in step (1) does not balance out, grab the group of three balls that is light or heavy and repeat step (2) described above.
If u= (u1,u2,u3) andv= (v1,v2,v3), then the dot product of u and v is u·v=u1v1+u2v2+u3v3. For instance, the dot product of u=i−2j−3kandv= 2j−kisu·v= 1·0 + (−2)·2 + (−3)(−1) =−1.
Properties of the Dot Product.
Let u,v, and w be three vectors and let c be a real number. Then u·v=v·u,(u+v)·w=u·w+v·w,(cu)·v=c(u·v).
Further, u·u=|u|2.
Thus, if u=0is the zerovector, then u·u= 0, and otherwise u·u>0.1
Orthogonality Two vectors u and v are said to be orthogonal(perpendicular), if the angle between them is 90◦.Theorem. Two vectors u and v are orthogonal if and only if u·v= 0.
Answer: 12
Step-by-step explanation:
-8 is 8 away from 0.
4 is 4 away from 0.
8+4 = 12
Hope this helps!
Answer:20,12
Step-by-step explanation:
32×5/8=20
32×3/8=12
