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3 years ago

Determine whether the ratios 1:1 and 6:6 are equivalent

Mathematics

2 answers:

ad-work [718]3 years ago

6 0

Answer:

its is because if you divide 6:6 by 6 it equals 1:1

Step-by-step explanation:

plz brainliest i need it to rank up

Mariana [72]3 years ago

4 0

Answer:

They are equivalent

Step-by-step explanation:

1:1 is the same as 6:6 because 6:6 is technically 1:1 when you divide both sides by 6.

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Finding the missing length

pav-90 [236]

$\huge\colorbox{black}{ \color{white}{ANSWER}}$

we know,

$\mathfrak{\hookrightarrow { area = \dfrac{1}{2} \times (a + b) \times h }}$

where,

a = 2 cm
b = 5 cm
area = 28 cm²

So,

$\hookrightarrow \mathcal{28 = \dfrac{1}{2} \times (5 + 2) \times h}$

$\hookrightarrow \mathcal{28 \times 2 = 7 \times h}$

$\hookrightarrow \mathcal{ \dfrac{56}{7} = h}$

$\hookrightarrow \mathcal{h = 8}$

so, missing lenght = 8 cm

6 0

3 years ago

Describe the composite transformation that has occurred.

Sidana [21]

Answer:

rotate CCW 90°, reflect across the x-axis
(x, y) ⇒ (-y, -x) . . . . . both transformations together

Step-by-step explanation:

The vertex order ABC is clockwise in the original figure and also in the first image: A'B'C'. The altitude from AC to B is up in the original and left in the first image, indicating a rotation 90° CCW.

The first transformation is a rotation 90° CCW.

The vertex order of A''B''C'' is CCW, indicating a reflection. The direction of the altitude from A''C'' to B'' is still to the left, so the reflection must be over a horizontal line. We find the x-axis bisects the segments A'A'', B'B'', and C'C'', confirming that it is the line of reflection.

The second transformation is reflection across the x-axis.

_____

Algebraically, the transformations are ...

1st: (x, y) ⇒ (-y, x)

2nd: (x, y) ⇒ (x, -y)

Both together: (x, y) ⇒ (-y, -x).

6 0

3 years ago

PLZ I'M BEING TIMED Which equation could have been used to create this table?

Talja [164]

Answer:

y=6x

Step-by-step explanation:

Let us assume the table is the one shown in the attachment.

We can observe the following pattern from the table:

$12=6*2$

$24=6*4$

$36=6*6$

$60=6*10$

$76=6*12$

Hence in general

$y=6*x$

Therefore the equation that could have been used to create this table is

$y=6x$

7 0

3 years ago

This is Algebra 2. help me

gladu [14]

(4x^2-25)/(2x-5)=14
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
$
a=4
b=-28
c=45
subsitute
x= $\frac{-(-28)+/- \sqrt{(-28)^{2}-4(4)(45)} }{2(4)} 
$
x= $\frac{28+/- \sqrt{784-720} }{8} 
$
x= $\frac{28+/- 8}{8} 
$
x= $\frac{5}{2} 
$ or $\frac{9}{2} 
$
if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used

answer is
x=9/2

3 0

3 years ago

A ball was dropped from a height of 150 cm. The rebound factor of the ball is

morpeh [17]

Letter c is correct 234

7 0

3 years ago