Question

This is Algebra 2. help me

Answer 1

(4x^2-25)/(2x-5)=14
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x  fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x=$\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
a=4
b=-28
c=45
subsitute
x=$\frac{-(-28)+/- \sqrt{(-28)^{2}-4(4)(45)} }{2(4)}$
x=$\frac{28+/- \sqrt{784-720} }{8}$
x=$\frac{28+/- 8}{8}$
x=$\frac{5}{2}$ or $\frac{9}{2}$
if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used


answer is
x=9/2