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Luda [366]
2 years ago
15

It is not possible to divide 5 by 0 because there is no number you can___ by 0 and get 5 .

Mathematics
1 answer:
elixir [45]2 years ago
5 0

Answer:

multiply

Step-by-step explanation:

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What is 514 times 33?
Iteru [2.4K]

Answer:

16,962

Step-by-step explanation:

Hope that helps lol.

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3 years ago
PLZ HELP ME What shape is this cross-section?
Irina18 [472]

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i'm not sure if i'm right but think is cube

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3 years ago
The scatter plot suggests a relationship between time and the distance from the destination. The equation of the line of best fi
viva [34]

Answer:

Strong Negative

Step-by-step explanation:

We already know that the answer is between c and d because the correlation coefficient negative.

We just have to figure out whether it is strong or weak.

In general, anything between -.7 and -1 is considered to have a strong correlation. -.8 is in between -.7 and -1 therefore the correlation is best described as strong negative.

4 0
3 years ago
Ashley and Kris are saving money for a vacation. Ashley currently has
USPshnik [31]

Answer:

Step-by-step explanation:

1) y = 50x + 2500

2) y = 200x + 1000

if we build a system with the two equations, we have:

50x+2500 = 200x + 1000

150x = 1500

x = 10

y = 2000 + 1000 = 3000

3) 10

4) $3000

8 0
2 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
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