Stan's, Mark's and Wayne's ages are 35 , 36 and 37 years respectively.
<em><u>Explanation</u></em>
Stan's, Mark's and Wayne's ages are <u>consecutive whole numbers</u> and Stan is the youngest and Wayne is the oldest.
So, lets assume that Stan's, Mark's and Wayne's ages are 
and 
Given that, the sum of their ages is 108. So, the equation will be.....
So, Stan's age is 35 years , Mark's age is (35+1)= 36 years and Wayne's age is (35+2)= 37 years.
The concept of the question above is Permutation where in we are to arrange to arrange the 6 students from which there are 20 students. This is the "permutation of 20 taken 6" or 20P6. The numerical value of the permutation is equal to 27907200.
A dime is a ten cent coin while a quarter is a 25 cent coin. The total of the money should be $8.40. Let x be the number of dime and y be the number of quarter. The equation that would best represent the given problem is,
0.1x + 0.25y = 8.40
x + y = 45
The values of x and y are 19 and 26, respectively. Thus, there are 19 dimes and 26 quarters.
