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Hunter-Best [27]

3 years ago

11

A caterer is preparing meals for a party of 78 guests. If about 1/4 of the guests want steaks, about how many steaks should the

caterer bring?

1 answer:

Ann [662]3 years ago

4 0

Answer:
You want to divide 78 by 4, so the answer will be 17.
And to check, 17x4=78, so it is correct.

You might be interested in

If f(x)= 5x, what is f^-1(x)?

Helen [10]

Step-by-step explanation:

$f( x) {}^{ - 1} \\ f(x) = 5x \\ y = 5x \\ x = 5y \\ y = \frac{x}{5} \\ f(x) {}^{ - 1} = \frac{x}{5}$

8 0

1 year ago

How can sums and differences of cubes be identified for factoring?

Ad libitum [116K]

The sum of cubes is given as:
a³ + b³ = (a + b)(a² - ab + b²)

Example for the sum of cubes:

64x³+y³ ⇒ This is the sum of cubes because each term; 64, x³, and y³ are cube numbers

By writing each term as an expression of cube numbers, we have:
(4x)³ + (y)³ ⇒ 64 is 4³
Use the factorization of the sum of cubes, we have:
(4x + y) ( (4x)²- 4xy + y²)
(4x + y) (16x² - 4xy + y²)

--------------------------------------------------------------------------------------------------------------

The difference of cubes can be factorized as:
(x³ - y³) = (x - y)(x² + xy + y²)

Example
(125x³ - 8y³) = (5x - 2y) ((5x)² + (5x)(2y) + (2y)²)
= (5x - 2y) (25x² + 10xy + 4y²)

7 0

3 years ago

Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911

nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

$\lambda=\dfrac{1}{2}$

(a) What is the expected number of 911 calls in one hour?

$\lambda=\dfrac{1}{2}\times 60=30$

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

$\lambda=\dfrac{1}{2}\times 5=2.5$

Number of calls = 3

So, P(X=3) is given by

$P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138$

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

$P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820$

Hence, a) 30, b) 0.2138, c) 0.0820

4 0

3 years ago

What time is it when the small hand is in between the 8 and 9 and when the big hand is at the 6?

Finger [1]

The time would be 8:30

3 0

3 years ago

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midni

Alex17521 [72]

Answer: It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

Step-by-step explanation:

Since we have given that

n = 84

x = 11

So, $\hat{p}=\dfrac{x}{n}=\dfrac{11}{84}=0.13$

p = 0.20

So, hypothesis:

$H_0:p=\hat{p}\\\\H_a:\hat{p}$

so, test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.13-0.20}{\sqrt{\dfrac{0.2\times 0.8}{84}}}\\\\z=-1.604$

At 1% level of significance, critical value would be

z= 2.58

Since 2.58>-1.604

So, We will accept the null hypothesis.

Hence, It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

4 0

2 years ago

Read 2 more answers