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2 years ago

Find the missing coefficient. (5d − 7)(5d − 6) = 25d2 ++ 42 5 65 –5 –65

Mathematics

2 answers:

Igoryamba2 years ago

7 0

Answer:

-65d

Step-by-step explanation:

(5d − 7)(5d − 6)

$(5d - 7)(5d - 6)$

Multiply it using FOIL method to find the missing term

Multiply 5d inside the second parenthesis and then multiply -7 inside second parenthesis

$5d \cdot 5d= 25d^2$

$5d \cdot -6= -30d^2$

$-7 \cdot 5d=-35d$

$-7 \cdot -6=42$

Now write all the terms together

$25d^2-30d-35d+42$

Combine like terms

$25d^2-65d+42$

HEre -65d is missing

andrew11 [14]2 years ago

3 0

I do believe it is -65d because the equation will look like this in the end
-65d=-65d.

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Mars2501 [29]

Answer:

Hi, there your answer will C. 85pi ft^2

Step-by-step explanation:

pi(5)(12)+pi(5)^2

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Hope this helps :)

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2 years ago

Mrs. Bailey gives a test, and her students’ scores range from 30 to 70. She decides to curve the scores, so that they range from

Harman [31]

Answer:

f(x) = x*3/4 + 42.5

Step-by-step explanation:

The original difference between the pair is 70 - 30 = 40

The new difference between the pair is 95 - 65 = 30

Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4

Then 30 * 3/4 = 22.5

Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95

Therefore, f(x) = x*3/4 + 42.5. We can test that

f(30) = 30*3/4 + 42.5 = 65

f(70) = 70*3/4 + 42.5 = 95

8 0

2 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

2 years ago

Write an equation of the line with the given slope and y-intercept,(4,3) and (0,1)

PSYCHO15rus [73]

Answer:

y=1/2x+1

Step-by-step explanation:

First use slope formula.

$\frac{y2-y1}{x2-x1}$

Plug in the information needed.

$\frac{1-3}{0-4}=\frac{-2}{-4}=\frac{1}{2}$

The slope is $\frac{1}{2}$ .

Now, use point-slope formula.

y-y1=m(x-x1)

Plug in the information needed.

y-3=1/2(x-4)

y-3=1/2x-2

y=1/2x+1

The equation of the line in slope-intercept form is y=1/2x+1.

Hope this helps!

If not, I am sorry.

5 0

1 year ago

Use the Triangle Inequality Property to determine whether a triangle can be formed with the given side lengths. 4 m, 8 m, 9 m *

Illusion [34]

Answer:

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene, isosceles, equilateral and so on.

The triangle inequality property states that the sum of any two sides of a triangle must be greater than the third side. If a, b and c are the sides of a triangle then:

a + b > c; a + c > b; b + c > a

Given a triangle with side length 4 m, 8 m, 9 m:

4m + 8m = 12m > 9m

4m + 9m = 13m > 8m

8m + 9m = 17m > 4m

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m.

7 0

2 years ago