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Lynna [10]
3 years ago
12

Prove: segment SD = segment PD

Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

C

Step-by-step explanation:

SD is congruent to PD and both triangles share the same side with each other.

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Explain how two amounts of change can be the same but the percent of change can be different
densk [106]
If I understand the question correctly, you can have the same amount of change be two different percentages by having 4 quarters and 100 pennies.
Each quarter is 25%
Each penny is 1%
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5 0
3 years ago
Find the area of the circle to the nearest tenth. use 3.14 for pie
VikaD [51]
I assume that 4.4 is the diameter,please do correct me if i am wrong.

To get the area of the circle,the formula is 丌r^2

to find the radius,we need ro devide the diameter by 2

thus the equations is
3.14  \times  ({4.4 \div 2})^{2}  \\  = 3.14 \times {2.2}^{2}  \\  = 15.196 \\  = 15.2(correct \: to \: the \: nearest \: tenth)
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3 0
3 years ago
Read 2 more answers
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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3 years ago
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kotykmax [81]


She shared 2/3 of her cupcakes


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The answer is 5 :>>>
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