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umka21 [38]
2 years ago
6

Mark and Don are planning to sell each of their marble collections at a garage sale. If Don has 5 more than 4 times the number o

f marbles Mark has, how many does each boy have to sell if the total number of marbles is 95 ?
Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0

Mark has 18 and Don has 77 number of marble to sell.

Let’s say Mark has x number of marble and Don’s marble number is y.

According to this problem we have,

Y = 4x +5

And x + y = 95

Or, x + 4x + 5 = 95

Or, 5x = 90

Or, x = 18 and y = 77  

Learn more about here:

brainly.com/question/13450942

#SPJ9

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Need help pls<br>thank you in advance ​
ira [324]

Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0
2 years ago
Questio
Olenka [21]

Answer:

  d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

  (6d +1)^2 + 12 = 13 . . . . given

  (6d +1)^2 = 1 . . . . . . . . . .subtract 12

  6d +1 = ±√1 . . . . . . . . . . take the square root

  6d = -1 ±1 . . . . . . . . . . . .subtract 1

  d = (-1 ±1)/6 . . . . . . . . . . divide by 6

  d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

  f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

4 0
3 years ago
ILL GIVE BRAINLIEST... HURRY PLZ
Alexeev081 [22]

12 Pairs

4 pairs = 8

2 pairs = 4

8 + 4 = 12

If you need total socks, there's 24 total

7 0
3 years ago
Select the ratio equivalent to 8:2<br>A. 24:10 <br>B. 4:2<br>C.4:1<br>D. 32:12​
Mama L [17]

Answer:

C)

Step-by-step explanation:

If you divide 8:2 by two you get 4:1 which is the equivilant ratio.

Hope this helps.

4 0
3 years ago
You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m
Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed  

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500\frac{N}{m}

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

mg y= \frac{1}{2} k x^{2}

mg(h +x) = \frac{1}{2} k x^{2}

By rearranging the above equation we get

k x^{2}  - 2mgx - 2mg h = 0

Put all the values in above equation we get

1500x^{2}  - 29.43 x - 26.48 = 0

By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0
3 years ago
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